The factors of 126 are: 1 2 3 6 7 9 14 18 21 42 63 126. The prime factors are: 2 x 3 x 3 x 7.
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The factors are 2, 3, 7, 9, 63, 6, 21, 42, 18, 1, and 126. ChaCha on!
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Do you mean prime factorization? Check out my Math Variety blog posts on prime factorization for an explanation of this concept, practice problems, and solutions. Click on ads/links
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f(x)=x^(3)+2x^(2)45x126 first we find zeros of given polynomial by putting x=3 f(3) = (3)^3+2(3)^245(3) 126 = 27+18+135126 = 153153 = 0 so (x+3) is a factor of this polynomial
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